An ideal gas expands from 17.0 l to 64.0 l at a constant pressure of 1.00 atm. then, the gas is cooled at a constant volume of 64.0 l back to its original temperature. it then contracts back to its original volume without changing temperature. find the total heat flow, in joules, for the entire process.

The total heat flow is Q = -24.46 J.

Explanation:

Transformation 1:

V₁ = 17.0 L

V₂ = 64.0 L

P = 1.00 atm

T₁ → T₂

T₁ < T₂

ΔU₁ = Q₁ + W₁

Transformation 2:

V = V₂ = 64.0 L

T₂ → T₁

T₁ < T₂

ΔU₂ = Q₂ + W₂, W₂ = 0 ∴ ΔU₂ = Q₂

Transformation 3:

T = T₁

V₂ → V₁

ΔU₃ = Q₃ + W₃,  ΔU₃ = 0 ∴  Q₃ = - W₃

ΔU is a state function, therefore the total ΔU = 0.

ΔU = ΔU₁ + ΔU₂ + ΔU₃ = 0

Q₁ + W₁ + Q₂ + 0 = 0

Q₁ + Q₂ = W₁

Q₁ + Q₂ = - PΔV

Q₁ + Q₂ =  -1.00 atm x (64.0 - 17.0)L

Q₁ + Q₂ = - 47.0 J

Q₃ = -W₃

Q₃ = - nRTln(V₁/V₂)

PV = nRT

nRT = 1.00 atm x 17.0L

Q₃ = - 17 x ln (17/64)

Q₃ = 22.54 J

Q = Q₁ + Q₂ + Q₃

Q = -47.0 + 22.54

Q = -24.46 J

the correct answer is answer a. a mixture

no other options make sense

hope this

have a great day : )

  - sprinkles

the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.