Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. the osmotic pressures required for this process can be as high as 18.1 atm . what would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 22 ∘c?

0.749 M

Explanation:

To solve this problem we use the formula

Where P is the osmotic pressure, M is the molar concentration, T is the temperature (in K) and R is the ideal gas constant 0.082 atm·L·mol⁻¹·K⁻¹

We put the data given by the problem and solve for M:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"