If 21 ml f gas is subjected to a temperature change from 10.0c to 120c and a pressure change from 1.0 atm to 15 atm, the new volume is:

1.9 ml
1.0 ml
0.53 ml
440 ml

V₂ = 1.41 mL

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 21 mL

Initial pressure = 1 atm

Initial temperature = 10 °C (10 +273 = 283 K)

Final temperature = 12 °C (12 +273 = 285 K)

Final volume = ?

Final pressure = 15 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/T₁ P₂

V₂ = 1 atm × 21 mL × 285 K / 283 K × 15 atm  

V₂ = 5985 atm .mL. K / 4245 K. atm

V₂ = 1.41 mL

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: