The air in a 4.00 l tank has a pressure of 1.20 atm . what is the final pressure, in atmospheres, when the air is placed in tanks that have the following volumes, if there is no change in temperature and amount of gas?

the second voulme is 2500 ml

P₂ = 1.92 atm

Explanation:

According to the boyle's law:

The pressure of given amount of gas at constant temperature and number of moles of gas is inversely proportional to the volume.

P₁V₁= P₂V₂

Given data:

Initial volume = 4.00 L

Initial pressure = 1.20 atm

Final volume = 2500  mL  

Final pressure = ?

Solution:

First of all we will convert the volume into litter.

2500 mL × 1L/1000 mL = 2.5 L

P₁V₁ =  P₂V₂

P₂ = P₁V₁ /V₂

1.20 atm×4.00 L = P₂ ×2.5 L

P₂ = 1.20 atm×4.00 L/ 2.5 L

P₂ = 4.8 atm. L/ 2.5 L

P₂ = 1.92 atm

i believe it is a.) released into

explanation:

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )