In a container there were 5 l of a gas at 25 °c. if the temperature decreases to -10 °c, what will be the new volume of the gas?

Okay, so this is a PV=NRT problem
We know that V1/T1 = V2/T2 from the formula.
T1 is given as 25 degrees
V1 is given as 5 Liters
If the temperature decreases by 10 degrees, then T2 would be 25-10, so V2 is 15

Now, we can plug everything into the formula
5/25 = T2/15
(5/25) * 15 = T2
Therefore, T2 = 5/25 * 15L. When you simplify this, you get 3L
Therefore, the new volume of the gas is 3L

Hope this helped ^_^

True, the standard unit for volume is liters which can be represented by either a lower case "l" or a capital "l"

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"