Abottle in lab is labeled [cocl2.6h2o] = 0.71 m in 9.217 m hcl. if you determine [cocl42-] to be 0.361 m at a particular temperature using absorbance measurements, what must be the value of [co(h2o)62+] in the solution at that temperature? express your response to three digits after the decimal.

[Co(H₂O)₆]²⁺ = 0.361 M

Explanation:

[CoCl₂ . 6H₂O] + 2Cl⁻ → [CoCl₄]²⁻ + 6H₂O

[Co(H₂O)₆]²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O

[CoCl₄]²⁻ = 0.361 M ∴ [Co(H₂O)₆]²⁺ = 0.361 M

The equation shows that the concentration of [Co(H₂O)₆]²⁺ should be equal to the concentration of [CoCl₄]²⁻.

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