Given the balanced equation:
hbraq) + naoh(aq) -
nabr (aq) + h2o
and remembering that
molarity = moles/liter
or
mmoles/ml
(1) (a) calculate the number of mmoles of hbr in 100.0 ml of 0.250 mhb
(b) calculate the number of mmoles of naoh in 100.0 ml of 0.250 mnoh
() when these two solutions are mixed the acid and base should neutralize one
another exactly. this means that all of the acid and base are completely used up;
either one could be considered a "limiting reactant". starting with the mmoles of
either the acid or base, calculate the number of mmoles of salt produced by the
reaction.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: