Using 25.0cm3 of aqueous lithium hydroxide, concentration 2.48mol/dm3, 2.20g of hydrated lithium sulfate was obtained. calculate the percentage yield, giving your answer to one decimal place.
2lioh h2so4 → li2so4 2h2o li2so4 h2o → li2so4.h2o
the number of moles of lioh used =
the number of moles of li2so4.h2o which could be formed =
mass of one mole of li2so4.h2o = 128 g
the maximum yield of li2so4.h2o =
percentage yield = % [4]
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Using 25.0cm3 of aqueous lithium hydroxide, concentration 2.48mol/dm3, 2.20g of hydrated lithium sul...
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