Find q when 22.0g of water is heated from 17.0 degrees celsius to 100 degrees celsius

When 22.0 g of water is heated from  17 °C  to 100 °C what amount of heat absorbed?

When 22.0 g of water is heated from  17 °C  to 100 °C  water absorbed   7643.64 j heat.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of water = 22.0 g

Initial temperature = 17°C

Final temperature = 100°C

Solution:

ΔT  = T₂ -T₁

ΔT  = 100°C - 17 °C= 83°C

Q = m.c. ΔT

Q = 22 g× 4.186 j/g °C × 83 °C

Q = 7643.64 j

It means water require more heat which is  7643.64 j to increase its temperature from 17  °C to 100  °C .

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.