Consider the reaction between no and cl2 to form nocl: 2no(g)+cl2(g)⇌2nocl(g) a reaction mixture at a certain temperature initially contains only [no]= 0.57 m and [cl2]= 0.66. after the reaction comes to equilibrium, the concentration of nocl is 0.27 m .

Value of the equilibrium constant is 1.5

Explanation:

Initial concentration of  = 0.57 M

Initial concentration of  = 0.66 M

Equilibrium concentration of  = 0.27 M

The given balanced equilibrium reaction is,

Initial conc.       0.57 M    0.66      0

At eqm. conc.   (0.57-2x)M (0.66-x)M   (2x)M

The expression for equilibrium constant for this reaction will be,

we are given : 2x= 0.27 M

x = 0.135 M

Now put all the given values in this expression, we get :

Thus the value of the equilibrium constant is 1.5

idk i'm not smart

explanation:

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