Which of the following shows the correct quantum numbers (n; ℓ; mℓ) and electron configuration for the highest energy electron(s) in the given atoms? 1. rb: [kr]5s 1 ; n = 5; ℓ = 0; mℓ = 0, 1 2. n: [he]2s 2 2p 3 ; n = 2; ℓ = 2; mℓ = −2, −1, 0, 1, 2 3. fe: [ar]4s 2 3d 6 ; n = 4; ℓ = 0; mℓ = 0 4. ca: [ar]4s 2 ; n = 4; ℓ = 1; mℓ = −1, 0+1 5. co: [ar]4s 2 3d7 ; n = 3; ℓ = 2; mℓ = −2, −1, 0, 1, 2

Co: [Ar]4s 2 3d7 ; n = 3; ℓ = 2; mℓ = −2, −1, 0, 1, 2

Explanation:

Hello,

Quantum numbers for the highest energy level of cobalt are correct, because n matches with the considered sub-orbital 3, l matches with the d region that has a value of 2 based on the rule: if region=s, l=0; if region=p, l=1;if region=d, l=2 and if region=f, l=3 and the ml goes from -2 to 2 including zero by taking into account the l quantum number. The rest of the options are wrong since the quantum numbers don't match with the corresponding orbitals.

Best regards.

catya your not at all which answer i've seen you do this on another question!