8.00 ml of nh3 is titrated directly from 32.6 ml of 0.4000 m hcl what is the concentration of the nh3 in the solution

1.63 M

The reaction between NH₃ and HCl is given by the equation;

NH₃(aq) + HCl(aq) → NH₄Cl(aq)

We want to calculate the concentration of ammonia solution.

Step 1: Calculate the number of moles of HCl used

To calculate the number of moles we multiply the molarity of HCl by the volume.

Moles = Molarity × Volume

          = 0.40 M × 0.0326 L

          = 0.01304 moles

Step 2: Determine the number of moles of NH₃

From the equation 1 mole of HCl reacts 1 mole of NH₃

Therefore, the mole ratio of HCl to NH₃ id 1 : 1

Hence, the number of moles of HCl are equal to the number of moles of NH₃

Number of moles of NH₃ = 0.01304 moles

Step 3: Calculate the concentration of NH₃

Molarity is the concentration of a solution in moles per liter

Molarity = Number of moles ÷ Volume

Number of moles = 0.01304 moles

Volume of NH₃ =8.00 mL or 0.008 L

Therefore;

Molarity = 0.01304 moles ÷ 0.008 L

            = 1.63 M

Therefore, the concentration of NH₃ IS 1.63 M

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