The slightly soluble ionic compound pbf2 has a solubility in water of 0.74 g/l. what is the numerical value of ksp for pbf2?

Ksp =  1.08 × 10⁻⁷

Explanation:

Given data:

Solubility of PbF₂ = 0.74 g/L

Ksp for PbF₂ = ?

Solution:

PbF₂ → Pb⁺² + 2F⁻

Number of moles dissolved = 0.74 g/L /245.2 g/mol

Number of moles dissolved = 0.003 M

[Pb⁺²] = 0.003 M

[F⁻] = 0.003 M × 2 =  0.006 M

Ksp = [Pb⁺²] [F⁻]²

Ksp = (0.003 ) (0.006 )²

Ksp =  (0.003 ) (3.6 ×10⁻⁵)

Ksp =  1.08 × 10⁻⁷

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.