Your teacher gives you a rectangular block of the
element silver (ag) that you mass at 886g, they tell you
that the metal has a density of 8.86g/ml. the sample
mesures 2cm by 4cm. what is the height of your
sample

Height = 12.5 cm

We are given ;

Mass of silver element = 886 g

Density of silver = 8.86 g/mL

The dimensions of the sample;

Length = 4 cm s

Width = 2 cm

We are required to find the height of the sample metal

Step 1: Calculate the volume of the sample

Density = Mass÷ Volume

Rearranging the formula

Volume = Mass ÷ Density

             = 886 g ÷ 8.86 g/mL

             = 100 mL

But,1 mL = 1 cm³

Therefore, Volume of the sample is 100 cm³

Step 2: Height of the sample

Volume = length × width × height

Rearranging the formula

Height = V÷ LW

           = 100 cm³ ÷ (2 cm × 4 cm )

           = 100 ÷ 8

           = 12.5 cm

Therefore the height is 12.5 cm

0.88m hope i am correct : )