If 9.71 ml of 0.252 koh is used to complete titrate 15.0 ml of hcl , how many moles of hcl are in the solution ?

0.00245 moles of HCl

We are given;

Volume of KOH = 9.71 mL

Molarity of KOH = 0.252 M

Volume of HCl = 15.0 mL

We are required to determine the number of moles of HCl  

The reaction between HCl and KOH is given by;

KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)

Molarity = Moles ÷ Volume

Rearranging the formula;

Moles = Molarity × Volume

          = 0.252 M × 0.00971 L

          = 0.00245 moles

From the equation, 1 mole of KOH reacts with 1 mole of HCl

Therefore, the mole ratio of KOH : HCl is 1 : 1

Thus,

Moles of HCl will be 0.00245 moles

Therefore, there are 0.00245 moles of HCl in the solution.

the link still does not work even when adding it to the url bar

explanation: