Asample of seaweed contains two liters of water and has 100 grams of salt dissolved in its cells. the seaweed is placed in a bucket with 4 liters of water and 300 grams of dissolved salt. what will occur when the system reaches equilibrium?

The seaweed will lose 0.5 L of water.

Explanation:

We can calculate the concentration of salt dissolvied in the sample of seaweed:

We can also calculate the salt concentration in the bucket:

Once the seaweed is placed in the bucket, it will act as a semipermeable membrane, allowing an osmosis process, in which water will move from the seaweed (the region with lower concentration) to the bucket (the region with higher concentration). So the seaweed will lose water until the salt concentration the seaweed and the bucket is the same.

It's possible to calculate how much water is transfered:

Because the concentrations are equal:

Now we solve for x:

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.