Some nitrogen is held in a 2.00-l tank at a pressure of 3.00 atm. the tank is connected to a 5.00-l tank that is completely empty (evacuated), and a valve is opened to connect the two tanks. no temperature change occurs in the process. determine the total pressure in this two-tank system after the nitrogen stops owing.

0.857 atm

Explanation:

The nitrogen stops owing when it fulfills both of the tanks (the gas molecules intend to fulfill all the space they are). So the tanks will have the same pressure, and the final volume will be the volume of the two tanks.

For Boyle's law:

P1*V1 = P2*V2

Where P1 is the initial pressure (3.00 atm), V1 is the initial volume(2.00 L), P2 is the final pressure, and V2 is the final volume (2.00 + 5.00 = 7.00 L).

3.00*2.00 = P2*7.00

7.00P2 = 6.00

P2 = 0.857 atm

answer; i believe the correct answer is (solid gold);

the answers would be

the first one and the second one