Calculate the ph of an aqueous solution of 16 ml of 0.00046 m hclo4(aq) after dilution to 42 ml.

1000 of HClO_{4} [/tex] contain 0.00046mol
16 of HClO_{4} [/tex] contain  x
                       x = 
                       x = 0.00000736mol


(0.00000736mol)(16)= 
         
                  =  0.000002803mol

pH= -log []
    = -log (0.000002803cm
    = 5.55
                                

The gas would begin to expand, and eventually the can would burst or explode.