If atmospheric pressure on a certain day is 749 mmhg, what is the partial pressure of nitrogen, given that nitrogen is about 78% of the atmosphere? 165 mm hg 760 mm hg 600 mm hg 584 mm hg 749 mm hg

584 mm Hg

Explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

where, x = mole fraction

= total pressure = 749 mmHg

Putting in the values we get:

The partial pressure of nitrogen will be 584 mmHg

explanation: