In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: co (g) + h2o (g) ⇌ co2 (g) + h2 (g) in an experiment, 0.35 mol of co and 0.40 mol of h2o were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.18 mol of co remaining. keq at the temperature of the experiment is

Equilibrium constant is 0.70.

Explanation:

Initial moles of   = 0.35 mole

Volume of container = 1 L

Initial concentration of

Initial moles of   = 0.40 mole

Volume of container = 1 L

Initial concentration of

equilibrium concentration of [/tex]

The given balanced equilibrium reaction is,

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

Thus the value of the equilibrium constant is 0.70.

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