Use the data given below to construct a born-haber cycle to determine the second ionization energy of ca. δ h°(kj) ca(s)→ca(g) 193 ca(g)→ca (g) e− 590 2o(g)→o2(g) - 498 o(g) e−→o−(g) - 141 o−(g) e−→o2−(g) 878 ca(s) 12o2(g)→cao(s) - 635 ca2 (g) o2−(g)→cao(s) - 34142o(g) > o2(g) - 498o(g) + e- > o-(g) - 141o-(g) + e- > o2-(g) 878ca(s) + 1/2 o2(g) > cao(s) - 635
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