Lithium acetate, lich3co2, is a salt formed from the neutralization of the weak acid acetic acid, ch3co2h, with the strong base lithium hydroxide. given that the value of ka for acetic acid is 1.8×10−5, what is the ph of a 0.289 m solution of lithium acetate at 25∘c?

Answer : The pH of 0.289 M solution of lithium acetate at is 9.1

Explanation :

First we have to calculate the value of .

As we know that,

where,

= dissociation constant of an acid =

= dissociation constant of a base = ?

= dissociation constant of water =

Now put all the given values in the above expression, we get the dissociation constant of a base.

Now we have to calculate the concentration of hydroxide ion.

Formula used :

where,

C is the concentration of solution.

Now put all the given values in this formula, we get:

Now we have to calculate the pOH.

Now we have to calculate the pH.

Therefore, the pH of 0.289 M solution of lithium acetate at is 9.1

answer: your mm

explanation:

answer; i believe that the correct answer is (a) potassium(k)