Ablock of copper of unknown mass has an initial temperature of 65.4 degress celcuis. the copper is immersed in a beaker containing 95.7 g water at 22.7 degress celcius. when the two substances reach thermal equilibrium, the final temperature is 24.2 degrees celcius. what is the mass of the copper block?

The answer to your question is: m = 37.88 g

Explanation:

Data

                  Copper                   Water

mass               ?                          95.7 g

Cp               0.092 cal/g°C        1 cal/g°C

T1                65.4°C                     22.7°C

T2                24.2°C                    24.2°C

Formula

                   Q copper = Q water

Q = mCp(T2 - T1)

                  - m(0.092)(24.2 - 65.4) = 95.7(1)(24.2 - 22.7)

                   m = 95.7(1)(24.2 - 22.7) /- (0.92)(24.2 - 65.4)

                   m = 143.55 / 3.79

                   m = 37.88 g

the answer is b. dilution

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