Asample of an unknown compound is vaporized at 170(degrees)c. the gas produced has a volume of 1980.ml at a pressure of 1.00atm, and it weighs 5.17g.

assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. round your answer to 3 significant digits. in g/mol.

The answer to your question is: 0.28 g/mol

Explanation:

Data

T = 170°C = 443°K

V = 1980 ml

P = 1 atm

m = 5.17 g

R = 0.082 (atm l)/(mol°K)

Formula

               PV = nRT

Process

             n = RT / PV

Substitution

             n = (0.082 x 443) / (1 x 1.98 l)

             n = 36.33 / 1.98

             n = 18.35 moles

Molar mass = 5.17 / 18.35

                   = 0.28 g/mol

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