A125g metal block at a temperature of 93.2 degrees celsius was immersed in 100g of water at 18.3 degrees celsius. given the specific heat of the metal (0.900 j/g degrees celsius), fund the final temperature of the block and the water

Explanation:

There are two heat transfers involved: the heat lost by the metal block and the heat gained by the water.

According to the Law of Conservation of Energy, energy can neither be destroyed nor created, so the sum of these terms must be zero.

Let the metal be Component 1 and the water be Component 2.

Data:  

For the metal:

For the water: