Glucose, c6h12o6,c6h12o6, is used as an energy source by the human body. the overall reaction in the body is described by the equation c6h12o6(aq) 6o2(g)⟶6co2(g) 6h2o(l) c6h12o6(aq) 6o2(g)⟶6co2(g) 6h2o(l) calculate the number of grams of oxygen required to convert 58.0 g58.0 g of glucose to co2co2 and h2o. h2o. mass of o2: o2: gg calculate the number of grams of co2co2 produced.

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

air quality

poor drinking water

and heavy polution

can lead to poor health