Unsaturated fatty acids are often classified according to the number of carbon atoms between the terminal methyl carbon (the omega carbon) and the closest double bond to the methyl end of the chain. an omega‑3 fatty acid, for example, would have a double bond in position 3 counting from the methyl end of the molecule. identify which omega class each fatty acid belongs to.

(1) palmitoleic acid
(2) oleic acid
(3) linoleic acid
(4) arachidonic acid

(a) omega 3
(b) omega 7
(c) omega 6
(d) omega 9

(1) Palmitoleic acid - (B) Omega 7

(2) Oleic acid - (D) Omega 9

(3) Linoleic acid - (C) Omega 6

(4) Arachidonic acid - (C) Omega 6

Explanation:

For unsaturated fatty acids, we can calculate the omega class with the following expression:

omega class = total number of carbons - position of the double bond closest to the omega carbon

(1) Palmitoleic acid

IUPAC name: (9Z)-hexadec-9-enoic acid

Total number of carbons: 16

Position of the double bond closest to the omega carbon: 9

Omega class: 7

(2) Oleic acid

IUPAC name: (9Z)-Octadec-9-enoic acid

Total number of carbons: 18

Position of the double bond closest to the omega carbon: 9

Omega class: 9

(3) Linoleic acid

IUPAC name: (9Z,12Z)-octadeca-9,12-dienoic acid

Total number of carbons: 18

Position of the double bond closest to the omega carbon: 12

Omega class: 6

(4) Arachidonic acid

IUPAC name: (5Z,8Z,11Z,14Z)-5,8,11,14-Eicosatetraenoic acid

Total number of carbons: 20

Position of the double bond closest to the omega carbon: 14

Omega class: 6

a is the answer to this question

explanation:

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.