A10.0g sample of h2o(l) at 23.0degrees c absorbs 209 joules of heat. what is the final temp of the h2o(l) sample? explain.

The answer to your question is: 28°C

Explanation:

Data

mass = 10 g

T1 = 23°C

T2 = ?

Q = 209 joules

Formula

Q = mC(T2 - T1)

T2 = Q/mC + T1

T2 = 209/(10 x 4.182) + 23

T2 = 4.99 + 23

T2 = 27.99 ≈ 28°C

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