Balance the following by redox. box the reducing agent and encircle the oxidizing agent. show your answer with explanation. you very much.

acidic:

1.) cr2o7-2 + i2 > cr+3 + io3-1

2.) as2o3 + no3-1 > h3aso4 + n2o3

Answer :

(1) act as a reducing agent and act as a oxidizing agent.

(2) act as a reducing agent and act as a oxidizing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

(1) 

In this reaction, 'I' is oxidized from oxidation (0) to (+5) and 'Cr' is reduced from oxidation state (+6) to (+3). Hence, act as a reducing agent and act as a oxidizing agent.

(2) 

In this reaction, 'As' is oxidized from oxidation (+3) to (+5) and 'N' is reduced from oxidation state (+5) to (+3). Hence, act as a reducing agent and act as a oxidizing agent.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.