How many grams of ca metal are produced by the electrolysis of molten cabr2 using a current of 30.0 amp for 8.0 hours?

of Ca

Explanation:

First we are going to write down the balanced reaction:

The reduction for the ion will be:

It means that 2 Faraday left for each mol of Ca.

Converting from Faraday to Coulombs:

Then we can apply the Faraday´s law:

where

m=mass in grams

M=molar mass

I=current

t=time in seconds

e-=number of electrons per mol

Replacing values:

of Ca

possibly, yes.

explanation:

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