Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50 degrees celcius and 101.325 kpa

Ideal gas equation.

Explanation:

Given that:

Pressure = 101.325 kPa

Also, P (kPa) = 1/ 101.325  atm

So, pressure = 1 atm

Temperature = 50°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (50 + 273.15) K = 323.15 K  

Volume = ?

n = 3.2 mole

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 3.2 mol × 0.0821 L.atm/K.mol × 323.15 K  

⇒V = 84.89 L