How many l of co2 at stp could be produced from the reaction of 2 l of ch4 at stp with 2 l of o2 at stp?

ch4+2o2-2h2o+co2
a 1l
b 2l
c 3l
d 4l

Option A = 1 L

Explanation:

Given data:

Volume of CH₄ = 2 L

Volume of O₂ = 2 L

Volume of CO₂ = ?

Solution:

First of all we will write balance chemical equation.

CH₄ + 2O₂   →  2H₂O  + CO₂

Number of moles of CH₄:

PV = nRT

n = PV/RT

n =  1 atm. 2 L / 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹

n = 2 atm . L / 22.43 atm. L. mol⁻¹

n = 0.09 mol

Number of moles of O₂:

PV = nRT

n = PV/RT

n =  1 atm. 2 L / 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹

n = 2 atm . L / 22.43 atm. L. mol⁻¹

n = 0.09 mol

Now we compare the moles of O₂ and CH₄ with CO₂ from balance chemical equation

                    CH₄       :       CO₂

                     1            :        1

                    0.09      :       0.09

                      O₂         :         CO₂

                       2          :           1

                     0.09      :           1/2×0.09 = 0.045 mol

Volume of  CO₂

PV = nRT

V = nRT / P

V = 0.045 mol × 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹  / 1 atm

V = 1.0092 L

Which is approximately equal to 1 L.

the answer is either b or c

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.