Amixture of kclo3 and kcl with a mass of 0.950 g was heated to produce o2. after heating, the mass of residue was 0.820 g. assuming all the kclo3 decomposed to kcl and o2, calculate the mass percent of kclo3 in the original mixture.

Explanation:

The given reaction will be as follows.

Molar mass of = 122.5 g/mol

Molar mass of KCl = 74.5 g/mole

Molar mass of = 32 g/mole

We assume that the mass of in the sample be x g

Therefore, the mass of KCl in the sample = 0.95 - x

Hence, moles of =

So, moles of KCl produced = moles of  =

or, mass of KCl produced =

Therefore, total mass of KCl = mass of residue = (0.95 - x) + = 0.820 g

                         -0.39x = 0.820 - 0.95

                             x = 0.33

Thus, % of in the original sample will be calculated as follows.

                      = 34.73%

Thus, we can conclude that mass % of is 34.73%.

the answer is barium and copper bromide