Combining 0.236 mol fe2o3 with excess carbon produced 16.4 g fe. fe2o3 3c⟶2fe 3co what is the actual yield of iron in moles

The actual yield of iron =  0.294 moles

Explanation:

Step 1: The balanced reaction

Fe2O3 +3C → 2Fe + 3CO

For 1 mole of Fe2O3 consumed, there is needed 3moles of Carbon to produce 2 moles of Fe and 3 moles of CO

Step 2: Calculate moles of Fe

Moles of iron  = mass of iron / Molar mass of iron

moles of iron = 16.4 g / 55.845g/mole = 0.294 mole

The actual yield of iron = 0.294 mole

Step 3: Fe2O3 is the limiting reactant, this means the 0.236 moles will completely react.

1 mole of Fe2O3 consumed, will produce 2 moles of Fe

This means 0.236 moles of Fe2O3 will produce 2*0.236 = 0.472 moles of Fe. This is the theoretical yield of iron.

The percentage yield = 0.294/0.472 * 100% = 62.29 %

The actual yield of iron =  0.294 moles

i believe the answer is three water molecules