Astock solution of hno3 is prepared and found to contain 13.5 m of hno3. if 25.0 ml of the stock solution is diluted to a final volume of 0.500 l, the concentration of the diluted solution is m.

(a) 0.270
(b) 1.48
(c) 0.675
(d) 270
(e) 675

Answer : The correct option is, (C) 0.675 M

Explanation :

Using neutralization law,

where,

= concentration of = 13.5 M

= concentration of diluted solution = ?

= volume of = 25.0 ml  = 0.0250 L

conversion used : (1 L = 1000 mL)

= volume of diluted solution = 0.500 L

Now put all the given values in the above law, we get the concentration of the diluted solution.

Therefore, the concentration of the diluted solution is 0.675 M

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