Occupational safety and health administration has set the limit on the maximum percentage of carbon dioxide (co2) in air a worker can breathe at 0.500% by mole. if dry ice (solid co2) is sublimating (becoming a gas) in a room at a rate of 0.880 mol/min, what is the minimum rate that fresh air has to be supplied to the room so that the concentration of co2 in the room doesn't exceed 0.500% by mole? assume the room is well mixed, and the volume of the solid dry ice does not change

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

X = 176 moles of Air/min

I hope it helps!

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .