Coal can be considered to be a binary mixture of non-combustible mineral matter (ash) and combustible organic material (coal). an as-mined coal stream (the feed f) containing 43 wt.% mineral matter (ash) is "beneficiated" (separated) in a dense-medium cyclone to produce a product p containing 8 wt.% mineral matter and a tailings t containing 71 wt.% mineral matter. determine the recovery of the combustibleorganic component (non-mineral matter) from the feed into the product.

be careful - you are not being asked to find the recovery of mineral matter (ash), but the recovery of the combustible component. however, all the concentrations are given in terms of the mineral matter.

give your answer as a percentage (not a fraction) rounded off to one (1) decimal place.

no

explanation:

go away, people want answers, not to hook up

beta decay is the answer

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j