The molecular weight of nylon 6-10 can be controlled by adding monofunctional reactant. assume that the ratio of diamine and diacid is 1: 1 and that the reaction is carried out to completion. find the molecular weight as a function of the amount of acetic acid added for 0 mol % acetic acid, 0.1 mol % acetic acid, 0.5 mol %1 acetic acid, and 1.0 mol % acetic acid, where the mole fraction of acetic acid is based on the moles of carboxylic acid groups in the mixture.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole