For the diprotic titration you will be performing in the lab your unknown solution will be a mixture of po43– and hpo42–. at the first equivalence point all of the po43- will have been converted to hpo42-, so the solution will now contain only hpo42– . in a similar calculation to that in the previous question, a student has found that their original solution contained 1.238 mmol of po43-. if reaching the second equivalence point consumed 21.85 ml more of 0.1041 m hcl, how many mmol of hpo42– were in the original sample? report answer to 3 decimal places. no units necessary.

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i'm pretty sure its b i might be wrong though!

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-