2kl + pb(no3)2 > 2kno3 + pbl2
determine how many grams of kl are required to produce 1.2g of pbl2-

a) 0.43g
b) 0.86g
c) 1.67g
d) 3.33g

Molar mass KI = 166.0028 g/mol   and Pbl₂ = 461.0089 g/mol

2 Kl + Pb(NO₃)₂ > 2 KNO₃ + Pbl₂

2 x 166.0028 g > 461.0089 g
           ? g KI > 1.2 g

Mass KI = 1.2 x 2 x 166.0028 / 461.0089

Mass KI = 398.40672 / 461.0089

Mass KI = 0.86 g

Answer B

hope this helps!

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