Benzyl acetate is one of the active components of oil of jasmine. if 0.125 g of the compound is added to 25.0g of chloroform (chcl 3 ), the boiling point of the solution is 61.82°c. what is the molar mass of benzyl acetate. (chloroform: kb = 3.63 °c/m; tb° 61.70°c)

Answer : The molar mass of benzyl acetate is 151.25 g/mol

Explanation :

Formula used for Elevation in boiling point :

or,

where,

= boiling point of solution =

= boiling point of chloroform =

= boiling point constant  of chloroform =

m = molality

i = Van't Hoff factor = 1     (for non-electrolyte)

= mass of solute (Benzyl acetate) = 0.125 g

= mass of solvent (chloroform) = 25.0 g

= molar mass of solute (Benzyl acetate) = ?

Now put all the given values in the above formula, we get:

Therefore, the molar mass of benzyl acetate is 151.25 g/mol

right

explanation:

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