Asolution, s1, of yellow #5 has an absorbance far outside the linear region of beer’s law. in order to determine the concentration of this solution, a serial dilution is performed. to make solution s2, 20.00 ml of s1 is diluted to 100.00 ml. to make solution s3, 25.00 ml of s2 is diluted to 100.00 ml. the absorbance of s3 is measured to be 0.628 at 430 nm using a 1 cm cuvette. use the true value of ε and calculate the concentration of solution s1.

The concentration of solution S1 is 5.17 x 10⁻⁴ M.

Explanation:

Bee'rs Law: A = εcl

A: absorbance = 0.628

ε: molar absoptivity = 2.43 x 10⁴ M⁻¹cm⁻¹

c: molar concentration

l:pathlength = 1 cm

S3:

c = A/εl

c = 0.628/2.43 x 10⁴ M⁻¹cm⁻¹ x 1 cm

c = 2.58 x 10⁻⁵ M

2.58 x 10⁻⁵ mol Yellow #5 1000 mL

2.58 x 10⁻⁶ mol Yellow #5  100 mL

S2:

2.58 x 10⁻⁶ mol Yellow #5 25.00 mL

                    x                       100.00 mL

                    x = 1.03 x 10⁻⁵ mol Yellow #5

S1:

1.03 x 10⁻⁵  mol Yellow #5 20.00 mL

                    x                       1000.00 mL

                    x = 5.17 x 10⁻⁴ mol Yellow #5

1 a

2 d

3 a

4 c

explanation:

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.