Be sure to answer all parts. kc for the reaction of hydrogen and iodine to produce hydrogen iodide, h2(g) + i2(g) ⇌ 2hi(g) is 54.3 at 430°c. determine the initial and equilibrium concentration of hi if initial concentrations of h2 and i2 are both 0.11 m and their equilibrium concentrations are both 0.045 m at 430°c. [hi]i = m [hi]e = m

Explanation:

Hello,

In this case, by writing the law of mass action for the specified chemical reaction one obtains:

Now, at the equilibrium one solves for the hydrogen iodide equilibrium concentration as:

Then, since there was a change in order to attain the equilibrium, one could compute such change by taking into account both the initial and the equilibrium concentration of either hydrogen or iodine to find:

Finally, at the equilibrium, the concentration of hydrogen iodide is defined via:

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