List the number of each type of atom on the left side of the equation 2c10h22(l)+31o2(g)→20co2(g)+22h2o(g )

enter your answers separated by commas (the order of the numbers is the same as the order of the elements on the left side of the equation).

20, 44, 62

Explanation:

To find the number of atoms of each element, we multiply coefficient and subscript  

For example contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So let us find the number of atoms of each element on the left  side of the equation  

Number of C atoms = 2 × 10 = 20

Number of H atoms = 2 × 22 = 44

Number of O atoms = 31 × 2 = 62

20, 44, 62  are the Answers.

i think   the answer is c hope i'm right