Write the chemical equation and the ka expression for the acid dissociation of each of the following acids in aqueous solution. first show the reaction with h+(aq) as a product and then with the hydronium ion. part a c6h5cooh. show the reaction with h+(aq) as a product. express your answer as a chemical equation. identify all of the phases in your answer. nothing request answer part b write the ka expression for the acid dissociation from the previous part. write the expression for the acid dissociation from the previous part. 1[h+][c6h5coo−] [c6h5cooh][h+][c6h5coo−] [h+][c6h5coo−][c6h5cooh] [h+][c6h5coo−]

The equation for the dissociation and expression for the acid dissociation constant of benzoic acid is written below.

Explanation:

We are given an acid known as benzoic acid having chemical formula of

The chemical equation for the dissociation of acid into its acid when dissolved in water follows:

The expression of acid dissociation constant for above equation follows:

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression. So, the concentration of water is not taken in account in the expression.

Hence, the equation for the dissociation and expression for the acid dissociation constant of benzoic acid is written above.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.