Compound 1 has a composition of 46.7 mass % of element a and 53.3 mass % of element b. a and b also form a second binary compound (compound 2). if the compositions of the two compounds are consistent with the law of multiple proportions, which of the following compositions could be that of compound 2? a. 23.4 mass % a 76.6 mass % b b. 30.4 mass % a 69.6 mass % b c. 33.3 mass % a 66.7 mass % b d. 53.3 mass % a 46.7 mass % b e. 73.3 mass % a 26.7 mass % b

The answer to your question is: B.

Explanation:

Law of multiple proportions: this law states that when 2 elements combine to form more than 1 compound the weights that one element that combines with a fixed weight and the other are with a ratio of small whole numbers.

Then, the proportion of B:A in compound 1 is:

                                                                           53.3/ 46.7 = 1.14

Options                                                         Ratio       Compare ratio

                                                                                     with compound 1

A. 23.4 mass % A 76.6 mass % B               3.27                2.87

B. 30.4 mass % A 69.6 mass % B               2.29               2

C. 33.3 mass % A 66.7 mass % B               2.0                  1.75

D. 53.3 mass % A 46.7 mass % B               0.88                0.77

E. 73.3 mass % A 26.7 mass % B               0.36                0.31

The answer is B because there is a proportion between this compond and compound 1.

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.