Aluminum had a specific heat of 0.215 cal/(g °c). when 25.7 cal (108.5 j) of heat is added to 18.4 g of aluminum at 20.0°c, what is the final temperature of the aluminum?

26.5°C

Explanation:

Heat added is the product of mass, specific heat capacity, and change in temperature.

q = mC(T − T₀)

25.7 cal = (18.4 g) (0.215 cal/g/°C) (T − 20.0°C)

T = 26.5°C

answer; i believe the correct answer is (solid gold);

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying