Amanometer (shown below) that is open to the atmosphere contains mercury (sg = 13.6) with a layer of oil floating on the mercury in the right leg. if the level of the mercury in the left leg is 2 cm above the mercury level in the right leg, and the oil layer on the right is 8 cm above the mercury level in the right leg. what is the density of the oil?

3400 kg/m³

Explanation:

Given:

Specific gravity of the mercury = 13.6

therefore, the density of mercury = 13.6 × 1000 = 13600 kg/m³

Level of mercury in the left limb = 2 cm above the mercury level in right limb

= 0.02 m

Level of oil layer in the right limb = 8 cm above the mercury level in right limb

0.08 m

Now,

Pressure in manometer is given as = ρgh

where,

ρ is the density

g is the acceleration due to gravity

h is the height of the liquid above datum

also,

pressure in right limb = pressure in the left limb  (for the equilibrium)

thus,

ρ₁gh₁ = ρ₂gh₂

here,

ρ₁ = density of oil

ρ₁ × g × 0.08 = 13600 × g × 0.02

or

ρ₁ = 3400 kg/m³

personal, she chose to do it.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error