20.0 ml sample of hcl, ist te of hel is titrated with 0.0300m koh solution. the volume of potassium droxide required is 27.50ml. what is the molarity of hci solution? +koh → kci+h2o

The molarity of HCl is 0.041 M.

Explanation:

To calculate the molarity of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is KOH

We are given:

Putting values in above equation, we get:

Hence, the molarity of HCl is 0.041 M.

the volume increases

the answer is na (sodium)