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Chemistry, 02.10.2019 20:30 catherinesquitieri
Balance the chemical reaction equation
p4(s)+cl2(g)→pcl5(g)
enter the coefficients in order, separated by commas (e. g., 1,2,3).
view available hint(s)
1,10,4
the balanced equation is
p4(s)+10cl2(g)→4pcl5(g)
calculations involving a limiting reactant
now consider a situation in which 28.0 g of p4 is added to 53.0 g of cl2, and a chemical reaction occurs. to identify the limiting reactant, you will need to perform two separate calculations:
calculate the number of moles of pcl5 that can be produced from 28.0 g of p4 (and excess cl2).
calculate the number of moles of pcl5 that can be produced from 53.0 g of cl2 (and excess p4).
then, compare the two values. the reactant that produces the smaller amount of product is the limiting reactant.
part b
how many moles of pcl5 can be produced from 28.0 g of p4 (and excess cl2)?
express your answer numerically in moles.
part c
how many moles of pcl5 can be produced from 53.0 g of cl2 (and excess p4)?
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Answers: 3
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You know the right answer?
Balance the chemical reaction equation
p4(s)+cl2(g)→pcl5(g)
enter the coefficients...
p4(s)+cl2(g)→pcl5(g)
enter the coefficients...
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